Forum Age - ubbDev

You are not logged in. [Log In] ubbDev » Forums » Community Development » HTML, CSS, Programming and MySQL
» HTML, JavaScript, and CSS » Forum Age

Topic Options

#109986 - 02/10/06 05:30 AM Forum Age
Raziel Junior Member Registered: 01/22/06 Posts: 11	Whats wrong with this code? var startDate = ['08','02','2006']; // Forum Age var sta = new Date(); sta.setDate(startDate[0]); sta.setMonth(startDate[1]-1); sta.setYear(startDate[2]); var cur = new Date(); var dif = cur - sta; var totalMonth = 0; var totalYear = 0; var totalDay = Math.floor(dif/(60 * 60 * 24 * 1000)) + 1; while(totalDay > 365) { totalDay -= 365; totalYear++; } while(totalDay > 30) { totalDay -= 30; totalMonth++; } var age = totalDay+' days'; if(totalMonth > 0) age += ', '+totalMonth+' months'; if(totalYear > 0) age += ', '+totalYear+' year'; age += '.';
Top

#109987 - 02/14/06 12:00 AM

Re: Forum Age

Brett

Moderator

Registered: 05/04/01
Posts: 992
Loc: Twinsburg, Ohio

The plus 1 on the totalday variable seems to throwing things off by one day. Fundamentally the month/year counts will be off due to the fact that (leap) years and every other month is not 30 days. Correcting this by taking into account such variations into months will be a hefty amount of javascript.

More or less out of boredom I cleaned up the code taking out the while loops

Code:

<script type="text/javascript">
<!--
var startDate = ['08','02','2005']; 

// Forum Age
var sta = new Date(startDate[2], startDate[1] - 1, startDate[0]);
var dif = (new Date() - sta) / 86400000; // milliseconds in day
var age, display = new Array(0, 0, 0);

// Find Years
if(dif >= 365) {
	display[0] = Math.floor(dif / 365);
	dif -= (display[0] * 365); // take days off total
}

// Find Months
if(dif >= 30) {
	display[1] = Math.floor(dif / 30);
	dif -= (display[1] * 30); // take days off total
}

// Find Days
display[2] = Math.floor(dif);

document.writeln(display[2] + " days, " + display[1] + " months, " + display[0] + " years");
-->
</script>

Top