There was a thread here the other day that got lost with the recent crash.

If I remember correctly, the question was what exactly does chomp do? This answers given were only partially right.

Chomp removes the last character of a string, if that character matches what $/ set to. $/ is set to n by default, so when you see chomp $myvar it is looking to remove a n from the end. If the end is not a n, nothing gets removed. This differs from chop in that the last characer, no matter what it is, is removed by chop.

If you have slurped an entire file into an array and want to remove the n from each element, simply doing chomp @myarray will take care of that.

perldoc -f chomp for more information

--mark



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Thank you for the clarification Mark... it's very much appreciated!

Yeah thanks Mark, that was the answer I really needed. I get it now...Thanks again!

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Wait, actaully can someone please tell me why a chomp is needed in this small script?

#!/usr/bin/perl
$classname = "CGI Programming 101";
print "Hello there. What is your name?n";
$you = <STDIN>;
chomp($you);
print "Hello, $you. Welcome to $classname.n";

Thanks, b/c Mark you said that if a character matches $/ Perl will automatically (by default) put a n right behind it right??

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When entering data via the standard input command, the user must hit enter to proceed, which means a n is also in the string. chomp is needed to remove it.

Feel free to correct Mark.

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All they have to do is drink beer, play hockey, and say "Eh"

* No offense meant to any Canadians

Atom, correct. When inputting via STDIN, hitting enter places a n on the end of your string, which must be chomp'd.



No, if the last character of the string matches what $/ is set to, it will be removed when chomp is called. $/ is set to n by default, but can be changed by the programmer if need be.

so if I have two strings:

$s1 = "My name is Markn";
$s2 = "blah blah blah";

chomp $s1;

will remove the n.

chomp $s2;

will do nothing to the string

--mark


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Ok thanks Mark & atom911, I get it now!


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